Question

If the temperature of air is increased from ${27}^{o}C$ to ${227}^{o}C$, in what ratio will the average kinetic energies of its molecule be increased?

Answer 1

${27}^{\circ }$ to ${227}^{\circ }c.$

ratio of K.E will be $\frac{E_1}{E_2}=E_1:E_2$

also ;

$\frac{E_1}{E_2}=\frac{T_1}{T_2}=\frac{27}{227}=27:227$