Question

If the temperature of the source is increased, the efficiency of the Carnot engine:

• A. decreases
• B. increases
• C. does not change
• D. will be equal to the efficiency of a practical engine

Answer 1

The correct option is B increases

Efficiency of Carnot Engine is

$\eta =1-\frac{T_2}{T_1}$

where,

$T_2=$ Temperature of the Sink

$T_1=$ Temperature of the Source

As the temperature of the source increases $\frac{T_2}{T_1}$ decreases and $1-\frac{T_2}{T_1}$ increases so efficiency increase.