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Question

If the term independent of x in the expansion of (32x213x)9 is k, then 18k is equal to:

A
5
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B
9
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C
7
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D
11
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Solution

The correct option is C 7
Tr+1= 9Cr(32x2)9r(13x)r
= 9Cr392r29r(1)rx183r
For the term independent of x
183r=0
r=6
T7= 9C6(3323)
k=718
18k=7

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