Question

If the terminal arm passes through the point (1, -1) making an angle $\theta$, then the value of sec $\theta$ is $\sqrt{m}$
Value of m is

Answer 1

The terminal point passes through (-1,1)
The distance from x -axis to the point, P = 1
The distance from y-axis to the point, B = 1
Thus, distance from the origin, H= $\sqrt{1^2+1^2}$ = $\sqrt{2}$
Let $\theta$ be the angle between the terminal arm and the origin,
$sec\theta =\frac{H}{B}=\frac{\sqrt{2}}{1}=\sqrt{2}$