If the the interquartile range is $12$ and third quartile is $20$ . Find the first quartile.

12

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8

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6

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4

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Solution

The correct option is D $8$
Interquartile range $=$ third quartile $-$ first quartile
$12 = 20 -$ first quartile
First quartile $= 20 - 12 = 8$ .

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If the the interquartile range is 12 and third quartile is 20. Find the first quartile.

The correct option is D 8Interquartile range = third quartile − first quartile12=20− first quartileFirst quartile =20−12=8.

If the the interquartile range is $12$ and third quartile is $20$ . Find the first quartile.

The correct option is D $8$
Interquartile range $=$ third quartile $-$ first quartile
$12 = 20 -$ first quartile
First quartile $= 20 - 12 = 8$ .