If the third term in the binomial expansion of (1+x)m is -18x2, then the rational value of m is
2
12
3
4
mc2=−18⇒m(m−1)2=−18⇒4m2−4m+1=0⇒(2m−1)2=0⇒m=12
If the thrid term in the binomial expansion of (1+x)m is - 18x2, then the rational value of m is
If the third term in the binomial expansion of (1+x)m is−x2, then the rational value of m is