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Question

If the third term in the expansion of [x+xlog10x]5 is 106 then x must be

A
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B
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C
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D
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Solution

The correct option is C
T3=T2+1=5C2x52(xlog10x)2
=10x3x2 log10x=10x(3+2 log 10x)=106 (given)x3+2 log10x=105
x=10 will satisfy this.

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