Question

If the third term of a G.P. is 4 then find the product of its first 5 terms.

Answer 1

Given that $a{r}^2$ = 4

Then product of first 5 terms

= $a\left(ar\right)\left(a{r}^2\right)\left(a{r}^3\right)\left(a{r}^4\right)$ = $a^5{r}^{10}$ = $[a{r}^2{]}^5$ = $4^5=1024$