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Question

If the three concurrent edges of a parallelepiped represent the vectors a,b,c such that [abc]=λ, then the volume of the parallelepiped whose three concurrent edges are the three concurrent diagonals of three faces of the given parallelepiped, is

A
2λ
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B
3λ
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C
λ
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D
None of these
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Solution

The correct option is D 2λ
The new edges of the new parallelepiped will be
(a+b),(b+c),(c+a)
Hence,
The parallelepiped thus formed will have a volume
[(a+b)(b+c)(c+a)]
=2[abc]
=2λ
Hence,
The volume of the new parallelepiped is equal to 2λ.

Hence, option A.

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