If the three distinct lines x+2ay+a=0,x+3by+b=0 and x+4ay+a=0 are concurrent, then the point (a,b) lies on
A
a circle
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B
a parabola
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C
an ellipse
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D
a straight line
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Solution
The correct option is D a straight line x+2ay+a=0…(1) x+3by+b=0…(2) x+4ay+a=0…(3) Solving (1) and (3), y=0,x=−a As given three lines are concurrent, so, (−a,0) will satisfy the equation (2) −a+b=0 ⇒a=b ∴ Locus of (a,b) is x=y which is a straight line.