If the three particles having their charges in the ratio of $1 : 3 : 5$ produce same spot on the screen in Thomson's experiment, then their masses will be in the ratio of

5 : 1 : 3

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5 : 3 : 1

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3 : 1 : 5

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1 : 3 : 5

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Solution

The correct option is B $1 : 3 : 5$
Since, spot is same, hence for the three particles $\frac{e}{m}$ should be same.
As $q_{1} : q_{2} : q_{3} = 1 : 3 : 5$
Hence, $m_{1} : m_{2} : m_{3} = 1 : 3 : 5$ .

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If the three particles having their charges in the ratio of 1:3:5 produce same spot on the screen in Thomson's experiment, then their masses will be in the ratio of

The correct option is B 1:3:5Since, spot is same, hence for the three particles em should be same.As q1:q2:q3=1:3:5Hence, m1:m2:m3=1:3:5.

If the three particles having their charges in the ratio of $1 : 3 : 5$ produce same spot on the screen in Thomson's experiment, then their masses will be in the ratio of

The correct option is B $1 : 3 : 5$
Since, spot is same, hence for the three particles $\frac{e}{m}$ should be same.
As $q_{1} : q_{2} : q_{3} = 1 : 3 : 5$
Hence, $m_{1} : m_{2} : m_{3} = 1 : 3 : 5$ .