If the time period of oscillation of mass $m$ suspended from a spring is $2$ sec, the time period of mass $4 m$ will be

2

Sec

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3

Sec

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4

Sec

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T

Sec

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Solution

The correct option is C $4$ Sec
$T = 2 π \sqrt{\frac{m}{K}}$

$\Rightarrow 2 = 2 π \sqrt{\frac{m}{K}}$
$T^{'} = 2 π \sqrt{\frac{4 m}{K}}$

$\Rightarrow T^{'} = 2 \times 2 π \sqrt{\frac{m}{K}}$
$T^{'} = 2 \times 2 = 4$ Sec

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If the time period of oscillation of mass m suspended from a spring is 2 sec, the time period of mass 4m will be

The correct option is C 4 SecT=2π√mK⇒2=2π√mKT′=2π√4mK⇒T′=2×2π√mKT′=2×2=4 Sec

If the time period of oscillation of mass $m$ suspended from a spring is $2$ sec, the time period of mass $4 m$ will be

The correct option is C $4$ Sec
$T = 2 π \sqrt{\frac{m}{K}}$

$\Rightarrow 2 = 2 π \sqrt{\frac{m}{K}}$
$T^{'} = 2 π \sqrt{\frac{4 m}{K}}$

$\Rightarrow T^{'} = 2 \times 2 π \sqrt{\frac{m}{K}}$
$T^{'} = 2 \times 2 = 4$ Sec