If the total energy of an electron in a Bohr orbit of a hydrogen atom is equal to -1, what will be the value of its kinetic energy?

-1

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Solution

The correct option is A 1
KE of an electron in Bohr's orbit $= + \frac{1}{2} \frac{e^{2}}{r_{n}}$
TE of an electron in Bohr's orbit $= \frac{- 1}{2} \frac{e^{2}}{r_{n}}$

$\frac{K E}{T E} = \frac{(+ \frac{1}{2} e^{2} / r_{n})}{(- \frac{1}{2} e^{2} / r_{n})} = - 1$

$K E = T E \times (- 1) = (- 1) \times (- 1) = 1$

$∴ K E = 1$

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