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Molecular Weight

If the total ...

Question

If the total mass of the mixture in the above case is $300 g m$ , the moles of $C (g)$ present ate.

A

\frac{1}{4}

mole

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B

\frac{4}{3}

mole

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C

\frac{3}{4}

mole

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D

None

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Solution

The correct option is C $\frac{3}{4}$ mole
$M o l s o f C = a α$ where a $= m o l e s o f^{'} A^{'} = \frac{300}{100}$
$\Rightarrow$ moles of C $= 3 \times 0. 25 = \frac{3}{4}$

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