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Question

If the total number of $$H_2$$ molecules is double of the $$O_2$$ molecules then the ratio of total kinetic energies pf $$H_2$$ to that of $$O_2$$ at 300 K is :-


A
1 : 1
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B
1 : 2
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C
2 : 1
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D
1 : 3
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Solution

The correct option is C 2 : 1
Kinetic energy for a single molecule is given as $$E=\dfrac{3}{2}kT$$
where $$k$$ is Boltzman's constant so for $$2n $$ molecules of Hydrogen the kinetic energy will be $$E_{H_2}=2n(1.5kT)$$
And that for $$n$$ molecules of $$O_2 $$ will be $$E_{O_2}=n(1.5kT)$$
ratio of energi$$es$$ will be $$E_{H_2} :E_{O_2}=2:1$$
Option C is correct.

Physics

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