Question

If the triangle ABC is revolved about the side $5$cm, then find the volume of the solid so obtained.

Answer 1

Cone is formed when $\Delta ABC$ is revolved about $5cm$
$r=12cm$
$h=5cm$

Volume of cone is given by,
$V=\frac{1}{3}\pi r^{2}h$

$\therefore V=\frac{1}{3}\times \frac{22}{7}\times (12{)}^2\times 5$

$\therefore V=\frac{1}{3}\times \frac{22}{7}\times 144\times 5$

$\therefore V=\frac{22\times 144\times 5}{21}$

$\therefore V=754.285c{m}^3$