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Question

If the two circles, x2+y2+2g1x+2f1y=0 and x2+y2+2g2x+2f2y=0 touches each other, then-

A
f1g1=f2g2
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B
f1g1=f2g2
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C
f1f2=g1g2
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D
None
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Solution

The correct option is B f1g1=f2g2
C1C2=r1±r2
(g1g2)2+(f1f2)2=(g21+f21±g22+f22)2
2g1g22f1f2=±2(g21+f21.g22+f22)2
g1f2g2f1=0
g1g2=f1f2
Ans: B

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