If the two circles x 2- y 3-2 g x -2 fy -0 and x 2- y 2-2 g 1 x -2 f 1 y -0 touch each other thenA- f 2- g 2- f 12- f 12B- fg 1- f 1 gC- ff 1- gg 1D- fg - f 1 g 1

The correct option is B fg1 = f1g |r_1 ± r_2|=c_1c_2 |√(g^2+f^2)±√(g_1^2+f_1^2)| = √((g g_1)^2 + (f f_1)^2 ) ⇒ gf_1=fg_1 ...

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Coaxial System

If the two ci...

Question

If the two circles $x^{2} + y^{3} + 2 g x + 2 f y = 0 a n d x^{2} + y^{2} + 2 g_{1} x + 2 f_{1} y = 0$ touch each other then

ff₁ = gg₁

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fg₁ = f₁g

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f² + g² = f₁² + f₁²

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fg = f₁g₁

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Similar questions

If the two circles $x^{2} + y^{2} + 2 g x + 2 f y = 0$ and $x^{2} + y^{2} + 2 g_{1} x + 2 f_{1} y = 0$ touch each other then

x^{2} + y^{2} + 2 g x + 2 f y = 0

x^{2} + y^{2} + 2 g_{1} x + 2 f_{1} y = 0

x^{2} + y^{2} + 2 g x + 2 f y = 0

x^{2} + y^{2} + 2 g_{1} x + 2 f_{1} y = 0

x^{2} + y^{2} + 2 g x + 2 f y = 0

x^{2} + y^{2} + 2 g^{1} x + 2 f^{1} y = 0

x^{2} + y^{2} + 2 g x + 2 f y = 0

x^{2} + y^{2} + 2 g_{1} x + 2 f_{1} y = 0

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