If the two equations x2−11x+a=0 and x2−14x+2a=0 have a common root and a≠0, then the value of the common root is
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Solution
Let α be the common root. α2−11α+a=0...(1)α2−14α+2a=0...(2) Subtracting (1) and (2), we get α=a3 Substituting α=a3 in equation (1), a29−11a3+a=0⇒a2−24a=0⇒a=24(∵a≠0)∴α=8