If the two feet of normals drawn from a point to the parabola x- - 6x - 4y -5 -0 be -7-3- and -1-3- then the third foot is -A- -1-0-B- -3-8-C- -3-1-D- -5-0-

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Points of Discontinuity

If the two fe...

Question

If the two feet of normals drawn from a point to the parabola x² - 6x - 4y +5 =0 be (7,3) and (-1,3) then the third foot is A) (1,0) B) (-3,8) C) (3,-1) D) (5,0)

Open in App

Solution

Suggest Corrections

Similar questions

y^{2} = 4 x

(1, 2)

(1, - 2)

x_{1}

3 y^{2} + 4 y - 6 x + 8 = 0

3

3 y^{2} + 4 y - 6 x + 8 = 0

(5, 0)

y^{2} = 4 x

P (1, 1)

A, B

C

A \equiv (0, 0)

B \equiv (3, - 1)

{(x - a)}^{2} + {(y + b)}^{2} = \frac{{(x + c y - 8)}^{2}}{10}

a + 2 b + c

Join BYJU'S Learning Program