If the two members of a Dobereiner triad are phosphorus and antimony, the third member of this triad is :

arsenic

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sulphur

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iodine

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calcium

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Solution

The correct option is B arsenic
According to Dobereiner, the atomic mass of the middle element was nearly equal to the arithmetic mean of the other two. Therefore, the atomic mass of the third element is $=$ $\frac{31 + 121.75}{2}$ $=$ 76.37 which is nearly equal to the atomic mass of arsenic.

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