If the unit of tension is divided by the unit of surface tension the derived unit will be same as that of

mass

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length

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area

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work

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Solution

The correct option is D length
Tension $= M^{1} L^{1} T^{- 2}$
Surface Tension $= \frac{f}{l} = \frac{M^{1} L^{1} T^{- 2}}{L^{1}} = M T^{- 2}$
$\frac{T e n s i o n}{S u r f a c e T e n s t i o n} = \frac{M^{1} L^{1} T^{- 2}}{M T^{- 2}} = L^{1}$

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The S.I unit of Surface tension is:

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