If the units of length and force are increased by four times, the unit of energy will be increased by:

16

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1600

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1500

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400

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Solution

The correct option is C $1500$ %
Energy $= M L^{2} T^{- 2} = F o r c e \times l e n g t h$
$L^{'} = 4 L$
$F^{'} = 4 F$
% Increase $= \frac{16 (F o r c e \times l e n g t h) - (f o r c e \times l e n g t h)}{(f o r c e \times l e n g t h)} \times 100$
$= 1500$ %

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