If the value of $a^{2} + b^{2}$ = 41 and ab = 20, find the value of a-b

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Solution

The correct option is A
1

Using the identity $(a - b)^{2}$ = $a^{2}$ + $b^{2}$ - 2ab

Substituting the given values,

$(a - b)^{2}$ = 41 -40

=1

Hence a-b = 1

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