Question

If the value of $a^2+b^2$ = 41 and ab = 20, find the value of a-b

• A. 1
• B. 2
• C. 0
• D. 3

Answer 1

The correct option is A

1

Using the identity $(a-b{)}^2$ = $a^2$ + $b^2$ - 2ab

Substituting the given values,

$(a-b{)}^2$ = 41 -40

=1

Hence a-b = 1