If the value of atmospheric pressure is $10^{6}$ dyne $c m^{- 2}$ , its value in SI units is

10^{4} N m^{- 2}

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10^{6} N m^{- 2}

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10^{5} N m^{- 2}

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10^{3} N m^{- 2}

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Solution

The correct option is C $10^{5} N m^{- 2}$
Pressure = $\frac{F}{A}$ $∵ 10^{6}$ dyne $c m^{- 2} = 10^{5} N m^{- 2}$ .

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Similar questions

If the value of atmospheric pressure is $10^{6} d y n e c m^{- 2}$ , then its value in SI units is:

900 {kgm}^{- 3}

1.01 \times 10^{5} {Nm}^{- 2}

(N / m^{3}, N / m^{2}, k g / m^{2}, P a / m^{2})

6.67 \times 10^{- 8}

{c m}^{2} {g m}^{- 2}

1 \times 10^{- 3} m^{3}

6.68 \times 10^{4} N m^{- 2}

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