Question

If the value of C.F.S.E for $Ni$ is ${\Delta }_0$ then it is for $Pd$ should be:

• A. $1.1{\Delta }_0$
• B. $0.5{\Delta }_0$
• C. $1.5{\Delta }_0$
• D. $2{\Delta }_0$

Answer 1

The correct option is C $1.5{\Delta }_0$

On going from $3d$ series to $4d$ series the ${\Delta }_o$ value increases 50%. Hence, for $Pd$ the CFSE = ${\Delta }_o+0.5{\Delta }_o$ = 1.5${\Delta }_o$. Therefore option $C$ is correct.