If the value of determinant - 1 sin x- cos x- 1 sin x- cos x- 1 sin x-y cos x- - is

The correct option is A independent of x For α=β=γ⇒Δ=0 ⇒Δ is independent of x ...

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Determinant

If the value ...

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If the value of determinant $∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 & s i n (x + α) & c o s (x + α) 1 & s i n (x + β) & c o s (x + β) 1 & s i n (x + γ) & c o s (x + γ) \end{matrix} ∣ ∣ ∣ ∣ ∣$ is

Independent of x,∝,β and γ

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independent of x

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Independent of ∝,β,γ

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independent of x,β,γ

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f (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} cos (x + α) + i sin (x + α) & cos (x + β) + i sin (x + β) & cos (x + γ) + i sin (x + γ) sin (x + α) - i cos (x + α) & sin (x + β) - i cos (x + β) & sin (x + γ) - i cos (x + γ) sin (2 β - 2 γ) & sin (2 γ - 2 α) & sin (2 α - 2 β) \end{matrix} ∣ ∣ ∣ ∣ ∣

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∣ ∣ ∣ ∣ ∣ \begin{matrix} s i n (x - α) & c o s (x - α) & a + x s i n α s i n (x - β) & c o s (x - β) & b + x s i n β s i n (x - γ) & c o s (x - γ) & c + x s i n γ \end{matrix} ∣ ∣ ∣ ∣ ∣

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