If the value of 2-5- -3-7 -1-6-3-2-1-14-2-5 is p-28- then p is equal to-

2 / 5 ×( 3 / 7 #160;) ( 1 / 6 × 3 / 2 )+( 1 / 14 × 2 / 5 ) = 6 / 35 1 / 4 + 1 / 35 = 24 35+4 / 35× 4 #160; = 55 / 35 ...

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Byju's Answer

Standard VII

Mathematics

Types of Fractions

If the value ...

Question

If the value of $\frac{2}{5} \times (- \frac{3}{7}) - (\frac{1}{6} \times \frac{3}{2}) + (\frac{1}{14} \times \frac{2}{5})$ is $\frac{p}{- 28}$ , then $p$ is equal to?

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Solution

$\frac{2}{5} \times (- \frac{3}{7}) - (\frac{1}{6} \times \frac{3}{2}) + (\frac{1}{14} \times \frac{2}{5})$
$= \frac{- 6}{35} - \frac{1}{4} + \frac{1}{35}$
$= \frac{- 24 - 35 + 4}{35 \times 4}$
$= \frac{- 55}{35}$
$= \frac{- 11}{28}$
$∴ p = 11$ .

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If the value of 25×(−37)−(16×32)+(114×25) is p−28, then p is equal to?

25×(−37)−(16×32)+(114×25)=−635−14+135 =−24−35+435×4 =−5535=−1128∴p=11.

If the value of $\frac{2}{5} \times (- \frac{3}{7}) - (\frac{1}{6} \times \frac{3}{2}) + (\frac{1}{14} \times \frac{2}{5})$ is $\frac{p}{- 28}$ , then $p$ is equal to?

$\frac{2}{5} \times (- \frac{3}{7}) - (\frac{1}{6} \times \frac{3}{2}) + (\frac{1}{14} \times \frac{2}{5})$
$= \frac{- 6}{35} - \frac{1}{4} + \frac{1}{35}$
$= \frac{- 24 - 35 + 4}{35 \times 4}$
$= \frac{- 55}{35}$
$= \frac{- 11}{28}$
$∴ p = 11$ .