Question

If the value of ${\left\{{\left(\frac{-2}{3}\right)}^{-2}\right\}}^2$ is $\frac{81}{m}$, then $m$ is equal to:

Answer 1

${\left\{{\left(\frac{-2}{3}\right)}^{-2}\right\}}^2$
$={\left\{{\left(\frac{3}{-2}\right)}^2\right\}}^2$
$={\left\{\frac{9}{4}\right\}}^2$
$=\frac{81}{16}$