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Question

If the value of En=78.4 kcal mol1, the order of the orbit in hydrogen atom is:


Your Answer
A
4
Your Answer
B
3
Correct Answer
C
2
Your Answer
D
1

Solution

The correct option is C 2
En=78.4 kcal mol1
=78.4×4.2 kJ mol1
=329.28 kJ mol1
=329.2896.5eV=3.4 eV
3,4 eV = 13.6 × Z2n23,4 eV = 13.6 × 1n2 n2 = 4 n = 2
This energy corresponds to 2nd orbit of H atom.

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