Question

If the value of equilibrium constant for a particular reaction is $1.6\times {10}^{12}$, then what will the system contain at equilibrium?

• A. 100% reactants
• B. Mostly reactants
• C. Mostly products
• D. Reactants and products in the ratio of $1:1$

Answer 1

The correct option is C Mostly products

Given, $K=1.6\times {10}^{12}$
Since the value of $K_{eq}$ is greater than ${10}^3$, the reaction proceeds nearly to completion.
Hence, $[P{]}_{eq}>>>[R{]}_{eq}$, i,e., mostly the products are present in the reaction mixture.

Thus, option (c) is the correct answer.