Question

If the value of $\underset{2}{\overset{10}{\int }}\left\{x\right\}dx.$ Where $\{\cdot \}$ denotes the fractional part of $x$ is $k$ then $4k=$

Answer 1

${\int }_a^b\left\{x\right\}dx=\frac{b-a}{2}$ where {$.$} is fraction part

of $x$ and $a$ and $b$ are integers.

${\int }_2^{10}\left\{x\right\}dx=\frac{10-2}{2}=4$.

hence $k=4$

so, $4k=16$