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Shape and Geometry Using VSEPR

If the value ...

Question

If the value of ionic radius ratio $(\frac{r_{c}}{r_{a}})$ is $0.52$ in an ionic compound, the geometrical arrangement of ions in crystal is:

A

Tetrahedral

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B

Planar

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C

Octahedral

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D

Pyramidal

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Solution

The correct option is A Tetrahedral
The value of ionic radius ratio is $0.52$ which is between $0.414 - 0.732$ , then the geometrical arrangement of ions in crystal is octahedral.

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Similar questions

Q. If the value of ionic radius ratio

(\frac{r_{c}}{r_{a}})

is 0.52 in an ionic compound, the geometrical arrangement of ions in crystal is

Q. The range of radius ratio (cationic to anionic) for an octahedral arrangement of ions in an ionic solid is:

Q. Two ionic solids

A B

C B

crystallize in the same lattice. If

\frac{r_{A^{+}}}{r_{B^{-}}}

\frac{r_{C^{+}}}{r_{B^{-}}}

0.50

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, respectively, then the ratio of edge length of

A B

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Q. If we know the ionic radius ratio in a crystal of ionic solid, what can be known of the following?

Q. Two ionic solids AB and CD crystallize in the same lattice.
If

\frac{r_{A^{+}}}{r_{B^{-}}}

\frac{r_{C^{+}}}{r_{B^{-}}}

0.50

0.70

respectively, then the ratio of edge length of AB and CD is :

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