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If the value ...

Question

If the value of ${log}_{10} 2 = 0.3$ and ${log}_{10} 3 = 0.5$ , then find the value of ${log}_{10} 6$ .

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Solution

${log}_{10} 6 = {log}_{10} (2 \times 3) {log}_{10} 6 = {log}_{10} 2 + {log}_{10} 3 {log}_{10} 6 = 0.3 + 0.5 = 0.8$

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{log}_{10} 2 = 0.3010

{log}_{10} 3 = 0.4771

, then the value of

{log}_{10} (2.25)

{log}_{10} 2 = 0.3010

{log}_{10} 3 = 0.4771

, then find the approximate value of

{log}_{10} 192

{l o g}_{10} 2 = 0.3010

{l o g}_{10} 3 = 0.4771

{l o g}_{10} 540 =

{log}_{10} 2 = 0.3010

{log}_{10} 3 = 0.4771

, calculate the values of:

log 250

l o g_{10} 2 = a

l o g_{10} 3 = b

3 x + 2 = 25

, the value of x in terms of

a

b

x = (10^{k} + 1)

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