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Multi-Electron Configurations and Orbital Diagrams

If the value ...

Question

If the value of (n + 1) is more than 3 and less than 6, then what will be possible number of orbitals?

6

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9

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10

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13

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Solution

The correct option is D $13$
n+ l sub orbit orbitals
4 3p 3
4 4s 1
5 4p 3
5 3d 5
5 5s 5
Total orbitals = $3 + 1 + 3 + 5 + 1$ = $13$

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