Question

If the value of (n + 1) is more than 4 and less than 6, then what will be possible number of orbitals?

Answer 1

$n+l$ Sub orbit Orbitals
$5$ $4p$ $3$
$5$ $3d$ $5$
$5$ $5s$ $1$
Total orbitals $=3+5+1=9$.