Question

If the value of $p=3x^{2}y,q=5y\text{and}r=2x^2$,
then find the value of $\frac{pqr}{10}$.

• A. $6x^2{y}^2$
• B. $3x^2{y}^2$
• C. $6x^4{y}^2$
• D. $3x^4{y}^2$

Answer 1

The correct option is D $3x^4{y}^2$

Given that,
$p=3x^{2}y,q=5yandr=2x^2$
$pqr=3x^{2}y\times 5y\times 2x^2$
$=3\times 5\times 2\times x^2\times x^2\times y\times y$
$=30x^4{y}^2$
Value of $\frac{pqr}{10}$$=\frac{30x^4{y}^2}{10}$
$=3x^4{y}^2.$