If the value of potential in an ac, circuit is 10V, then the peak value of potential is

\frac{10}{\sqrt{2}}

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10 \sqrt{2}

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20 \sqrt{2}

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\frac{20}{\sqrt{2}}

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Solution

The correct option is B $10 \sqrt{2}$
$V_{0} = \sqrt{2} V_{r m s} = 10 \sqrt{2}$

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