If the value of $\sec \theta$ is 1, what is the value of $ta{n}^2\theta$?

The correct option is C 0
Since $sec\theta =1$, $se{c}^2\theta =1$.

Since $1+{\tan }^2\theta ={\sec }^2\theta$
$\Rightarrow$$1+{\tan }^2\theta =1$
$\Rightarrow$${\tan }^2\theta =0$

Mathematics