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Trigonometric Ratios

If the value ...

Question

If the value of sin θ is $\frac{4}{5}$ , then find the value of $\frac{s e c θ}{c o s e c θ}$ .

A

\frac{5}{4}

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B

\frac{4}{3}

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C

\frac{5}{3}

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D

\frac{3}{4}

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Solution

The correct option is B $\frac{4}{3}$
The correct option is C

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θ

is in the first quadrant and

cos θ = \frac{3}{5}

, then the value of

\frac{5 tan θ - 4 c o s e c θ}{5 s e c θ - 4 cot θ}

s e c θ = \sqrt{2}

θ

lies in first quadrant . Find value of

\frac{1 + t a n θ + c o s e c θ}{1 + c o t θ - c o s e c θ}

s e c θ + t a n θ = p

, then find the value of

c o s e c θ

cos θ = \frac{3}{4}

then the value of

\sqrt{\frac{sec θ - c o s e c θ}{sec θ + c o s e c θ}}

θ = \frac{3}{4}

\sqrt{\frac{s e c θ - c o s e c θ}{s e c θ + c o s e c θ}} = \frac{1}{\sqrt{7}}

.

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