If the value of sin x- x-tan x is a- find 156 a-

For the angle x in a right angled , sinx is defined as opposite side/Hypotenuse. Similarly sec x = Hypotenuse/opposite = 1/cos x tanx = opposite/Adjacent From ...

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Standard XI

Mathematics

Trigonometric Ratios Using Right Angled Triangle

If the value ...

Question

If the value of sinx + secx + tanx is a, find 156a.

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Solution

For the angle x in a right angled $△$ , sinx is defined as

$\frac{o p p o s i t e s i d e}{H y p o t e n u s e}$ . Similarly sec x = $\frac{H y p o t e n u s e}{o p p o s i t e}$ = $\frac{1}{c o s x}$

tanx = $\frac{o p p o s i t e}{A d j a c e n t}$

From this $△$ , we get

sinx = $\frac{5}{13}$

secx = $\frac{13}{12}$

tanx = $\frac{5}{12}$

$\Rightarrow$ sinx + secx + tanx = $\frac{5}{13}$ + $\frac{13}{12}$ + $\frac{5}{12}$

$\Rightarrow$ a = $\frac{294}{156}$

$\Rightarrow$ 156 a = 294

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If the value of sinx + secx + tanx is a, find 156a. __

For the angle x in a right angled △, sinx is defined as opposite sideHypotenuse. Similarly sec x = Hypotenuseopposite = 1cosx tanx = oppositeAdjacent From this △, we get sinx = 513 secx = 1312 tanx = 512 ⇒ sinx + secx + tanx = 513 + 1312 + 512 ⇒ a = 294156 ⇒ 156 a = 294

If the value of sinx + secx + tanx is a, find 156a.

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