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Question

If the value of the determinant ∣ ∣a111b111c∣ ∣ is positive, then (a,b,c>0)

A
abc>1
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B
abc>8
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C
abc<8
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D
abc>2
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Solution

The correct option is C abc>8
we have
∣ ∣a111b111c∣ ∣=abc(a+b+c)+2
Δ>0abc+2>a+b+cabc+2>3(abc)1/3[A.M>G.Ma+b+c3>(abc)1/3]
x3+2>3x[x=(abc)1/3]x33x+2>0(x1)2(x+2)>0xϵ(2,1)(1,)x>2(abc)1/3>2abc>8

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