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Question

If the value of x2ax12 is 20 at x=4, then find the value of a.

A
4
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B
2
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C
-4
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D
-2
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Solution

The correct option is C -4
Value of exprssion x2ax12 is 20 at x=4.
So, let's first put x=4 in the given expression.
42a×412=20164a12=2044a=204a=204=16a=4

Hence, option 'c' is correct.

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