If the value of x2−ax−12 is 20 at x=4, then find the value of a.
A
4
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B
2
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C
-4
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D
-2
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Solution
The correct option is C -4 Value of exprssion x2−ax−12 is 20 at x=4.
So, let's first put x=4 in the given expression. ⟹42−a×4−12=20⟹16−4a−12=20⟹4−4a=20⟹−4a=20−4=16⟹a=−4