If the values of x,y,z and p are 1,2,3 and 4 respectively, then find the value of xy+zp.
A
80
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B
81
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C
82
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D
83
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Solution
The correct option is C 82 Given: x=1,y=2,z=3andp=4 Substituting these values in the equation xy+zp, we get xy+zp=12+34=1+81=82. Therefore the value of xy+zp=82