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Question

If the values of x,y,z and p are 1,2,3 and 4 respectively, then find the value of xy+zp.

A
80
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B
81
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C
82
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D
83
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Solution

The correct option is C 82
Given: x=1,y=2,z=3andp=4
Substituting these values in the equation xy+zp, we get
xy+zp=12+34=1+81=82.
Therefore the value of xy+zp=82

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