Question

If the vapours behave ideally at 1000 K determine the average translational kinetic energy of a molecule

• A. $2.07\times {10}^{-20}J$
• B. $3.07\times {10}^{-20}J$
• C. $4.07\times {10}^{-20}J$
• D. $5.07\times {10}^{-20}J$

Answer 1

The correct option is A $2.07\times {10}^{-20}J$

Average $KE=\frac{3}{2}\frac{RT}{N}=\frac{3}{2}KT$

$\frac{3}{2}\times 1.38\times {10}^{-23}\times 1000=2.07\times {10}^{-20}J$