Mean Deviation about Mean for Continuous Frequency Distributions
If the varian...
Question
If the variance of the following frequency distribution : Class10−2020−3030−40Frequency2x2
is 50, then x is equal to
A
4.00
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B
04
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C
4
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D
4.0
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Solution
xififixixi−¯¯¯x(xi−¯¯¯x)2fi(xi−¯¯¯x)215230−1010020025x25x0003527010100200∑fi=4+x∑fixi=100+25x∑fi(xi−¯¯¯x)2=400
Mean : ¯¯¯x=∑fixi∑fi=100+25x4+x ⇒¯x=25