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Question

If the vector ¯¯¯r=λ^i+2^j^k along a line makes angles α,β,γ with the coordinate axes then sin2α+sin2β+sin2γ=......

A
1
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B
2
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C
1+λ2
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D
1λ2
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Solution

The correct option is B 2
¯¯¯r=λi+2jk
cosα=λλ2+4+1=λλ2+5
cosβ=2λ2+5=2λ2+5
cosγ=1λ2+5=1λ2+5
cos2α+cos2β+cos2γ=λ2+5λ2+5=1
(1sin2α)+(1sin2β)+(1sin2γ)=1
sin2α+sin2β+sin2γ=2
B)Ans.

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