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Question

If the vectors a,b, and c from the sides BC,CA, and AB, respectively of a ABC's, then


A

a·b+b·c+c·a=0

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B

a×b=b×c=c×a

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C

a·b=b·c=c·a

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D

a×b+b×c+c×a=0

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Solution

The correct option is B

a×b=b×c=c×a


Explanation for the correct option :

Applying the triangle law ,

As vectors a,b,c form the side of ABC's so by triangle law a+b+c=0.

Take cross product by a on both sides:

a×a+b+c=a×0a×a+a×b+a×c=00+a×b+a×c=0a×b=-(a×c)a×b=c×a

Similarly by taking cross product by b and c it can be shown that a×b=b×c and b×c=c×a respectively.

Thus, it is shown that a×b=b×c=c×a.

Hence, the correct option is B.


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