If the vectors →P=a~i+a^j+3^kand→Q=a^i−2^j−^k are perpendicular to each other then the positive value of a is
A
zero
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B
1
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C
2
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D
3
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Solution
The correct option is B 3 Given, perpendicular, implies →P.→Q=0 or, (a^i+a^j+3^k).(a^i−2^j−^k)=0 or, a2−2a−3=0 Solving the quadratic, we get, a=3 or −1.